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-80=5x^2-100x
We move all terms to the left:
-80-(5x^2-100x)=0
We get rid of parentheses
-5x^2+100x-80=0
a = -5; b = 100; c = -80;
Δ = b2-4ac
Δ = 1002-4·(-5)·(-80)
Δ = 8400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8400}=\sqrt{400*21}=\sqrt{400}*\sqrt{21}=20\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{21}}{2*-5}=\frac{-100-20\sqrt{21}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{21}}{2*-5}=\frac{-100+20\sqrt{21}}{-10} $
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